How to calculate your Helium miner's transmit scale | Everything about HIP17 hex and reward scales - BEST HELIUM MINER

How to calculate your Helium miner’s transmit scale | Everything about HIP17 hex and reward scales

you might have knew that your hotspotis alone in your hex but the reward scale or the give magnitude is still less than one orthe configuration around your hotspot has not changed at all but your honor talent still wentdown and you are wondering why that happened in this video we will have an in-depth discussionon how alter magnitude or the transmit proportion is calculated along with a detailed understandingof hexes at different resolutions hey folks this is roy and welcome back to my canal eigentechyou might think that if you are alone in your hex at settlement 8 your reward magnitude of thetransmit flake is always going to be 1 but that is not actually genuine tell us check afew problematic precedents so here i am showing you a hex where there existed one hotspot as youcan see here and there are no hotspots around this hex the only outspots are prettyfar so this the reward scale for this one should have been one but you can seeit’s not one it’s instead 0.69 so what’s wrong here another example is i am showing youhere let me turn on the disseminate magnitude now um so you can see there by the cluster ofhot spots now these sixes has actually single hot spots inside it and these three have two hotspots inside it so you can see that for this and this hex uh the disseminate scale is one but for someunknown reason this the hot spots in this hex have only 0.5 which should have shouldn’t have been thecase it should have your scale of one so why is it so so in the first part of this video i’ll giveyou a immediate ask of how the disseminate knowledge are calculated and what could be the problems and thesecond part i will give you a more detailed answer for the quick answer we will go tothe browser and type app.hotspotty.net and once it loads we can click on this searchicon here and nature the appoint of your hotspot in this case we’ll check this problematic hotspot andi have already loaded its information and then you go to the reward scaling tab now and that willshow you uh some details about the wages of this particular hotspot so this is the net or totalreward magnitude which is 0.69 so let us now check the breakdown of the compensation magnitude after differentresolutions so you might already know that uh to estimate the reinforce magnitude the numberof hotspots at different resolutions are used in particular starting from resolution 10 all the way up to resolution 4. So in this case you can see that the calculated reward scale fordifferent answers are principally punishment starting from resolution 10 all the way up to resolutionfive but the problematic hex is resolving four and there are 363 too many hotspots they aresupposed to be uh so 800 would therefore be the optimal number of hot spots and because there are3 63 more distinguishes your proportion is 0.69 you can check that so the numeral is basically 800 divided among 800 plus 363 which is 1163 and that gives you 0.68787 so it’s 0.69 nearly so too uh this app isnice it goes to show uh in ruby-red pigment the spotlit below which one is the problematic hex and youcan see for the other actions successfully occupied fully occupied which is fine which means that thenumber of hot spot in that resolution is equal to the optimal number of hot spots and then thereare four more available at resolution seven twenty four ever accessible six and so on and uh on thetop of this page in the delineate it shows you the this colored hex shows you the problematic outcomes okayso in this case nothing can be done because uh the problem is at much larger scale so there is nohope for this one i am showing you another example now where the reverse scale is only 0.15 verybad and in the dislocation you can see there are questions at various flake starting from resolution1 0 primacy 8 7 and 5 but what is important here resolution 10 represents it’s really tiny spaceand if you click on here you will see that as mostly the two hotspots are very close toeach other and if one moves it slightly apart the area provides the site either this one moves hereobviously moves here ah the reverse scale for this particular um hex which is resolution 10 will goto one and to then to calculate the final resolving what you have to do that you have to simplymultiply uh to get the final or net wage proportion or move proportion you have to multiplyuh that your scale at all different solvings that will give you the final reward science and ahthe other questionable one which one as this one so nice jet black zebra i have also loadedit now and you can see that the problem is only at decide 10 which signifies two hotspots are really really close to each other you can see in this map it’s very close soin this case the simple solution is to move uh one of these hotspots slightly apart sofor example let’s say this one to ah x a at settlement 10 and that will solve the problem andyou don’t need to even physically move it because this is a very close distance uh you can always seta site which is within 50 to 100 meters of the actual physical location and that should still befine in terms of earning or watching each other i hope you now understand better how to estimate thetotal remuneration skill given the reward skill at individual resolutions and you will be also ableto perform diagnosis at which answer the problem exists if your payoff proportion is not one ifthe problem happens at a very high resolution like settlement 10 or solution 9 hex then there is achance to fix it by reasserting the location but if it happens at a much broader resolution likeresolution four or five ah there is not much hope because it ah involves a much much larger areaand you cannot change the site of other hotspots of course all right give us now move tothe second part of this video where we will have an in-depth discussion on how to really computethe disseminate ability for that first we need to have a good understanding of the hexagons at differentresolutions in this presentation i am showing you hexagons at different resolutions starting fromresolution 11 all the way up to resolution 4. So higher the amount signifies the finer it is so thesmaller the area and a smaller resolution necessitates a larger area so if you talk about the weapon lengthit starts from 30 meter for settlement 11 for this resolution 10 66 meter and it goes all the way upto 22.6 rhythm six kilometer for solving four if you take the rate between any uh consecutiveuh hex for example 66 rhythm by 30 meter uh between uh basically arm segment otherwise 10 hex dividedby s11 hex is going to be 62.646 and it’s going to be the same if you take the proportions of 1.22 kilometer divided among 461 kilometer so mostly this is the ratio of any two consecutivepairs so resolving rx divided by resolution r plus 1 x so this was the arm span if you look atthe area which is more interesting so uh range of solving 10 x divided by resolution 11 x isgoing to be 7 and again it’s going to be same for any two consecutive age so what does thisseven number mean it actually has a physical make so if we considered uh hexes as a at resolutioneight and seven these are not up to scale uh and give us suck seven resolve eights whichare contiguous in this fashion then you can see that the resolution 7x will look like this soseven solution eight hexes are enclosed inside one settlement seven hex okay and in this case itwill call that resolution seven is the parent hex and resolution eight is the child hex okay and ifyou now consider seven uh solution seven hexes as shown by this green hexagons here then theparent resolution six hexagon will look like this and this is true for any any resolution so onehex at solving r will be equal to seven hex at solving r in terms of area okay we can have abetter understanding of the hexagon disintegration by looking at a interactive map for that wewill go to the browser and sort helium fleck region then we will turn on the resolution 8 hex bytoggling this button here close it and then zoom in to any locale you prefer and give it load andthen i’ll click on some blot now and you can see that now this uh red zone is the bad area whereyou should not have any other hotspot if there is a hotspot at the centre for human rights and this black hexagonsare the resolution eight hexagon okay then let me now vanish now and turn on resolution nine as welland now you can see that inside one solving eight hex there are seven solution nine hexessimilarly as i told you it’s true for any um for any resolution hexes so i will turn this off andturn the resolution 7 on and then if you zoom out a little bit you can see now that inside aresolution 7 hex there are at present 7 settlement 8 hexes so the outside hex will be called the parentheticand the inside axis will be called the child hex now this might ogle a little bit confusing becauseyou can see that some part of this resolution eight hex is outside the parent hex okay butto see a more clearer picture we can go back to the hot spotty page earlier i presented you thisresolution 10 hexagon now we can go back and let’s scroll down now and click on resolution eight hexand it will now show you the proper borderline it looks like a kind of a bloom mold okay so thisis how the actual uh this is the actual shape of the hex that is actually used in the calculationsbut for the purpose of this video we’ll keep it simple and use regular hexagons as i registered youin the presentation so the next important spot is to understand the number of hot spots thatis optimal for a leaved resolution because that is the number which defines your individualreward knowledge so there are some default counts which is uh so resolving 11 is not considereduh star exclusively resist starting constitution 10 is considered and the default number of hotspots is one and one for location nine and then it increases gradually and goes to 250 for resolutionfour okay so i call this quantity in excerpt which you can contemplate as the maximum number of miners uh thatcan be present in a dedicated hex before the move flake is reduced below one so if your hotspotnumber for example let’s say at seven excess six uh the transmit scale all of all of them uh willgo down and it is increasingly becoming five divided among six but this number is actually not static it’sdynamic and that introduces in the intricacy uh so the end clip value actually increases fromthis default value to a maximum quality uh it increases gradually and under certain conditionsare met and the maximum values are still it’s one for decide 10 for 9 it’s 2 4 20 and forresolution 4 it’s 800 okay in the later part of this video we’ll discuss ways this n excerpt numberincreases from default value to this maximum value and under what kind of conditions so let us nowtake the default values here and try to compute the transmit magnitude for a imparted hotspot okay so ihave grayed out the rules and regulations 11 and it is not being used and then this is showing you then clip counts which are the default values so here i have prepared a table and showingyou the time multitude the same lists are here for different resolves okay and this next rowis showing you the number of miners at different resolution hexes so at uh from starting from 10 up to resolution eight there were one miner so basically if you have a minor in any childx you’ll ever have that minor in in in its planet x okay so in resolving seven there areeight eight minus 20 90 now and 300 okay so the formula to calculate transmit scale at individualhexes is given by this so hex transmit scale is minimum of either 1 or n divided among n minus sowhat it means that you have to divide in excerpt this list by n child and if this numeral is smallerthan 1 then “youre using” that count but if this list is larger than one “youre using” one here one importantpoint to remember is that the n minor is defined as the number of interactive miners theinteractive miners represents those hot spot which has which have place held and haveuh whose beacon signals have been witnessed by other horsepower in other words its lighthouse signalshould have a valid weakness right okay so those are the interactive hotspots and non-interactivehotspots are have always zero wage magnitude so um so we can simplify this math expressionand simply compute the ratio between n excerpt and n minor so if it’s greater than one you say trueif it’s less than one it will you say it false in other words if the number of minor present in hexis smaller or equal to the number of uh optimal number of hot spots it’s true or green and if it’smore than that it’s false so if it’s true uh you can consider that the disseminate flake is simplyone for that particular hex but when it’s fallaciou you have to take the fraction so in this case fivedivided by 8 which is 0.625 and now 250 divided among 300 which is 0.833 and then to compute the netor total transmit scale we have to just multiply all these amounts together since 1 doesn’t matterwe just proliferate 6 to 5 with 833 and that gives you 0.521 that would be the reverse scale ofthis particular minor with this configuration now if you just simply let’s say somebodyelse supplements another hotspot at resolving eight okay so it was earlier only your hotspot butanother hotspot uh comes at solution eight so then you have to add one hotspot for uh allthe resolutions up to so from eight all the way up to four and then since in this case this alsobecomes false also you have to take the ratio between n time and n adolescent here which is0. 5 and other multitudes somewhat get amended and now the total transmit scale will be themultiplication of the product of these three points and that becomes 0.231 so you cansee that it converted drastically earlier it was 0.5 and now it became 0.23 it’s just not afactor of 2 is more than a factor of 2 in such cases so “youre seeing” the reward proportion went downmainly because there was the limitation was only one hotspot at solution 8 hex before the reversescale is clipped however this count in time can change as i told you earlier this is a dynamicnumber so in this next responsibility we are trying to try to understand how that happens and when thathappens and in that case you have to too consider its neighbor so in this picture i am showing youseven resolution eight hexes representatives to blue-blooded and then uh this is the hex under considerationwhere we are going to neighbourhood our hotspot and these are there its neighbours and the dashedline in purple goes to show the resolution seven hex and notice that the neighbors can be placedin a different parent pates okay um so the parentheses for this resolution eight hex is thisone the bottom one but these ones have a different parent so since there are no hot spots around theend clip is set to its default value which is one so if i now place one hotspot in this hex youryour talent shown by color is going to be 1.0 however if i sit two hot spots that is somewhatoptimal and that is why the diversification is going to going to go down by such factors of 2 and becomes willbecome 0.5 inside this hex for this particular hex but this can change depending on the number ofsaturated neighboring hex so i am simply calling exactly exerting a call saturated hex which basicallymeans how many neighbours are there which have n minor or the number of children in that x largerthan or equivalent to n clip which is the default value which constitutes one here in this case so uh here is atable which shows you that that what should be this enabled value after which the end clip can beupgraded and it has different multitude for different solving so we are considering resolution eightso therefore spotlit it in bold so it has to be two in such cases so right now a neighboris zero because there is no hot spots around it so which is less than in saturation so the endclip is still going to be one now i place another one in its neighbor so that overrule magnitude is goingto be 1.0 however since in neighbor is one which is less than in saturation in clip is still goingto be one so this reward scale doesn’t improve now i place another hotspot in at its neighbor andthe neighbor now n neighbor is similar to two which is equal to the n saturation okay and uh so thesenumbers are on chain variable digits which i have picked up from f17 um information and nowthis nk time can be upgraded because it fulfills this condition it becomes now 2 and thus this yourscale no longer need to be 0.5 but it becomes 1.0 okay so now i can further increase it so ifi place another hotspot in another neighbor so now end neighbor is three so in clip can alsobe three so you can place three hotspots inside resolution eight hex without the wage scalebeing uh fetch down okay you add another it becomes four but can it keep increasing can youplace like six neighbours and can this become six no because there is again a limitation on thiswhich is uh represented by this n max list and again it is different for different resolutionsfor solution eight this is four okay but that meant that even though they are i sit um five hot spots inthis neighbor the maximum number of hot spots that i can place now without the reverse skill beinggone down being brought down is still going to be four so with four hot spots you can still haveyour scale of one uh also in this scenario the situation for other other access also improve forexample for this hotspot you have two neighbors with a two neighbours with having more than onehot spot so it can have now at peak of two hot spots with a overturn flake of 1.0 similarly thishex has three neighbors and so that this can have three hotspots inside it similarly this one threethis one three and this one two okay if you now increase another hotspot now since extremity excerpt hasbeen maxed out it’s still for your knowledge is going to go down the factor will be 4 divided among 5which is 0.8 uh so if you place for example 6 hotspots here it will be 3 divided by 6 whichis 0.5 and again if i increase the number of hotspots in this hex to 10 because the numberof granted what distinguish was simply two it the reverse scale for each of the hotspots becomes pointtwo and so note that uh these is these counts are obtained by considering there are no otherhotspots around it and then finally this was the these are the transmission scales for thisparticular resolution which is resolution eight but to get the final or net channel magnitude youhave to take the product of transmission skills and at all resolutions as i testified you earlierso and although i demo you this particular example for answer 8 the same explanationholds for all the distributions but the crowd in saturation and in max will be differentand these are the chain variable multitudes okay another important interpretation of this table isthat under no circumstances a hotspot can have a switch skill equivalent to 1 if the total number ofhot spots in that hex becomes larger than this in max number for example if you considerresolution 6 hex if the total number of hot spots in that resolution hex becomes larger than 100 all hotspots inside that hex including its child hexes the reinforce flake is going to be smaller thanone okay now i will answer a few commonly asked questions the first one is what is a good rewardskill in this table i have parted the reinforce or channel proportion in 5 different categories anythingbetween 0.95 and 1 would be excellent between 0.75 to 0.95 would be good mediocre would be 0.5 to0. 75 0.25 to 0.5 0 is 4 and anything below 0.25 is terrible okay so you’d like to be in the rangeyou’d like to have a reverse scale in the range of 0.75 to 1. The second question is how does thereward proportion feign your ironing so actually the reward proportion of your hotspot doesn’t affect yourironing directly it rather feigns the ironing of other hotspots in your proximity so basicallywhenever you send a beacon signal and it is received by other hotspots as a legitimate witnessthe making will be scaled down by the factor of your channel flake however it can affectyour earnings indirectly so make us check that uh so here is a seven hexes atresolution solution eight and this is the distribution of hot spots since thereare two neighboring hotspots have the saturated are saturated the end clip for this hex is goingto be two and there could be two hotspots with a switch proportion of one so if these hotspots sendsa become signal and received by this hotspot then with a legitimate with this let’s say it can give pointone operator okay um this is because the reverse scale is one it is not be scaled down similarlyuh another witness by this hotspot will also make spot 1 hnt nonetheless let’s say these twohotspots are pretty close to each other let’s say within answer 10 then you know that theyour proportion is going to go down to 0.5 as i pictured you earlier in the presentation and in that casewhat will happen that the beacon signal sent by this hotspot will be received by this but itwill become an invalid witness because saying that it’s too close to each other or most likelythe rssi value is too high so you can see that the reverse skill has indirectly affecting yourearning because you are you can no longer earn from this hotspot so it’s saying that that inthat case that your science is saying that there are other hot spots in your vicinity and one needs tomove those around to either you have to move your satan or the other beings have to move theirsand also in this case this hotspot also gives less hmd i could have earned object one earlier butsimply because that spot allegation this one will make now 0.05 worker and that is how you cansee that the turning of its neighbouring hotspots is effect but you can still lose weaknessesand that is how you can lose your earnings and the third question is how routinely is thisreward skill informed it can it can get updated whenever a brand-new hotspot arrives in your hex so itcould be any uh starting from resolution 10 to all the way up to resolution four so if a new hotspotscomes or the spot is assigned inside that hex the reverse skill might get updated similarly ifa hotspot loses or gains its interactive status as i justified earlier either your ability can getmodified as well and you can expect that you are skill changing a few times a day i hope with thisinformation you will be now able to understand how the honor proportion is calculated and then alsoperform diagnosis at what solving height the problem exists if your decide if your reversescale is less than one and again to reiterate if their own problems or the reverse scale is small atthe higher settlement like decide 10 or answer 9 you can most likely fix it by simplyreasserting its place uh if it happens if the problem exists at a much larger resolution likeresolution four five or six you cannot really do anything because it because it uh involves so manyhot spots in a very large widespread area i hope this information was useful to you and clarifysome of your indecisions if you have any more question let me know in the comment section that’s all fortoday thanks for watching chaps and get kryptonized

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